SOLUTION: 'Suppose exactly half of all customers are loyalty program members. Find the probability that more than half of the 20 customers are loyalty program members'.
It is a binomial
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It is a binomial
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Question 737345: 'Suppose exactly half of all customers are loyalty program members. Find the probability that more than half of the 20 customers are loyalty program members'.
It is a binomial question.
What I have so far:
pr(more than half of 20 customers are members)
pr(x greater than or equal to 11)
= 1-Pr(x is less than or equal to 10)
Using cumulative binomial distribution tables, because the question stated that the probability is more than half, I chose the probability of 0.6.
Then: 1-Pr(x is less than or equal to 10)
=1-0.2447
= 0.7553
Is this correct? Answer by Susan-math(40) (Show Source):
You can put this solution on YOUR website! No your p is wrong. Exactly half are loyalty members so p = 0.50 for the population.
The greater than half part has to do with you sample of 20 and you accounted for that already.
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