SOLUTION: Given x3-64 = ( x+a ) ( x2+bx+c ) what are the values of a, b and c. Enter your answer as a list [in brackets], in the form: [a, b, c]

Algebra ->  Expressions -> SOLUTION: Given x3-64 = ( x+a ) ( x2+bx+c ) what are the values of a, b and c. Enter your answer as a list [in brackets], in the form: [a, b, c]       Log On


   

Question 73734: Given
x3-64 = ( x+a ) ( x2+bx+c )

what are the values of a, b and c. Enter your answer as a list [in brackets], in the form: [a, b, c]
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Using the difference of cubes forumla:
m%5E3-n%5E3+=+%28m-n%29%28m%5E2%2Bmn%2Bn%5E2%29
We can see that m=x and n=4 (since 4^3=64) So a=-n,b=n, and c=n^2. Since n=4, a=-4, b=4, and c=16 (just match the variables). So the answer is [-4,4,16].