SOLUTION: The product of three consecutive odd integers is reduced by 23. That result is 99 less than the cube of the sum of the number 2 and the smallest of the three consecutive odd intege

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Question 737144: The product of three consecutive odd integers is reduced by 23. That result is 99 less than the cube of the sum of the number 2 and the smallest of the three consecutive odd integers.
Determining the mean of the three consecutive odd integers is your task
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

(x-2)(x)(x+2) - 23 = (2 + (x-2))^3 - 99
x^3 - 4x - 23 = x^3 - 99
-4x = -76
x = 19

mean of integers = middle integer = x = 19