log a - log b = log (a/b).
log ((7x+33)/6) = log(4x-3)
raise 10 to the power of both sides of the equation. That will remove the log (base 10). 10 ^ (log((7x+33)/6) = (7x+33)/6. 10^(log(4x-3)) = 4x-3.
(7x+33)/6 = 4x-3
7x+33 = 24x-18
51 = 17x
3=x
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