SOLUTION: Find an equation for line with y-intercept 3 that is perpendicular to the line y=(2/3)x-4. If f(x)=x^2 + 5, Find f(a+b)-f(a).

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find an equation for line with y-intercept 3 that is perpendicular to the line y=(2/3)x-4. If f(x)=x^2 + 5, Find f(a+b)-f(a).       Log On


   



Question 73691: Find an equation for line with y-intercept 3 that is perpendicular to the line y=(2/3)x-4.

If f(x)=x^2 + 5, Find f(a+b)-f(a).



Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

Find an equation for line with y-intercept 3 
that is perpendicular to the line 

y=%282%2F3%29x-4

Compare that to the "slope y-intercept" form

y=m%2Ax%2Bb

and you see that the slope is m=2%2F3 

Now we use the rule:

If a line has slope A%2FB then 
1. A line parallel to it will ALSO have slope A%2FB
2. A line perpendicular to it will have slope -B%2FA
(Note: if the slope is a whole number and
not a fraction, write it over 1, so it will be
in the form A%2FB)

A line perpendicular to a line with slope 2%2F3 will
therefore by the 2nd rule above have slope -3%2F2

Now all we have to do is use the slope y-intercept form

y=m%2Ax%2Bb

this time with m=-3%2F2 and b=3, so we have

y=%283%2F2%29x%2B3

If f%28x%29=x%5E2+%2B+5, Find f%28a%2Bb%29-f%28a%29. 

First find f%28a%2Bb%29 by replacing x by %28a%2Bb%29

f%28a%2Bb%29=%28a%2Bb%29%5E2%2B5

Now find f%28a%29 by replacing x by a

f%28a%29=a%5E2%2B5

So f%28a%2Bb%29-f%28a%29 = %28%28a%2Bb%29%5E2%2B5%29-%28a%5E2%2B5%29 = %28a%2Bb%29%5E2%2B5-a%5E2-5 =

%28a%2Bb%29%5E2-a%5E2 = %28a%2Bb%29%28a%2Bb%29-a%5E2 = a%5E2%2Bab%2Bab%2Bb%5E2-a%5E2 =

2ab%2Bb%5E2

Edwin