Question 736666: Using whole units and the area given, find the dimentions of the rectangle with the shortest perimeter. Area=188. My teacher told me to do a multiplication problem with numbers similar to each other. I've tried 13x13,13x14,14x12,12x15(which might not be close enough together) and 12x17. Nothing has worked. Please help. Thanks!
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! we know length (l) * width (w) = Area (A) for a rectangle and
2*l + 2*w = Perimeter (P)
we are given l * w = 188 (A)
let's list the factors as pairs (l, w) when multiplied together give 188
(188, 1), (94, 2), (47, 4)
it remains to calculate the pair with the smallest perimeter
(188, 1) = 2*188 + 2*1 = 378 (P)
(94, 2) = 2*94 + 2*2 = 192 (P)
(47, 4) = 2*47 + 2*4 = 102 (P)
therefore the rectangle with length 47 and width 4 has the shortest Perimeter
|
|
|
