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Learn this rule: (A + B)³ = A³ + 3A²B + 3AB² + B³
In your problem
(2a + 5)³
comparing that with the above substitute 2a for A and 5 for B
(2a + 5)³ = (2a)³ + 3(2a)²(5) + 3(2a)(5)² + (5)³
= 8a³ + 3(4a²)(5) + 3(2a)(25) + 125
= 8a³ + 60a² + 150a + 125
Edwin
