Question 736466: 1. x^4 + 3x^2 - 4 =0
Answer by sofiyac(983)   (Show Source):
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x^4 + 3x^2 - 4 =0
(x^2 + 4)(x^2 - 1) =0
(x^2 + 4)(x+1)(x-1) =0
x^2 + 4=0 or x+1 =0 or x-1=0
x^2 = -4 or x+1 =0 or x-1=0 solve for x
x=2i or x=-1 or x=1
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