SOLUTION: a painter starts painting a house which has 1/5 been done, 7 hrs later the work total work done in the house is 2/3, calculate the rate and express what units have been used.
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Question 736380: a painter starts painting a house which has 1/5 been done, 7 hrs later the work total work done in the house is 2/3, calculate the rate and express what units have been used.
we r studying slope intercept in linear equations Answer by GratefulGeek(3) (Show Source):
You can put this solution on YOUR website! What we know:
beginning of day: house is 1/5th painted
end of day: house is 2/3rd painted
from beginning to end of day: 7 hours has passed What we want to know:
(A) At what rate does the painter work?
(B) And, what units do we use to measure this?
SOLUTION:
(1) Find the difference of the portion of the house that is painted at the beginning of the day and the portion of the house painted at the end of the day.
Let b = beg. = 1/5
e = end = 2/3
x = portion of house painted between beg. and end of day
Now,
So, the painter painted 7/15 of the house in 7 hours.
(2) Now express this as a rate:
Since the painter painted 7/15 of the house in 7 hours it is easy to see he/she painted 1/15 every hour.
ANSWER
Finally we can say that the rate of painting is (A) 1/15 house per hour, (B) where house and hour are our units.
