SOLUTION: 7 liters of an acid solution was mixed with 3 liters of a 15% acid solution to make a 29% acid solution. what is the percent concentration of the first solution? how to form a tabl
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Question 736332: 7 liters of an acid solution was mixed with 3 liters of a 15% acid solution to make a 29% acid solution. what is the percent concentration of the first solution? how to form a table that shows this ?
You can put this solution on YOUR website! Would you be satisfied with a rational equation using the percentage concentrations instead of a table?
The target solution concentration achieved was T%. The available starting solution apparantly of lower concentration was v liters of L% acid. You are given v and L. The higher concentration H% acid was also used, call this amount u. You also know the value of u but you want to solve for H.
You mixed u liters of L% acid with v liters of H% acid and this made a solution resulting in T% acid. You do not know H but wish to find it.
EQUATION FOR THE TARGET RESULTING PERCENT ACID SOLUTION:
Solve for H. That will give a formula for H.
FINDING VALUE OF UNKNOWN:
u = 3 liters
v = 7 liters
L = 15%
H = UNKNOWN percent concentration, higher than 29
T = 29%
Substitute the given values to get the value of H.
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