SOLUTION: John wants to measure the height of a tree. He walks exactly 100 feet from the base of the tree and looks up. The angle from the ground to the top of the tree is 33º. This particul
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-> SOLUTION: John wants to measure the height of a tree. He walks exactly 100 feet from the base of the tree and looks up. The angle from the ground to the top of the tree is 33º. This particul
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Question 736309: John wants to measure the height of a tree. He walks exactly 100 feet from the base of the tree and looks up. The angle from the ground to the top of the tree is 33º. This particular tree grows at an angle of 83º with respect to the ground rather than vertically (90º). How tall is the tree?
Thanks,
paulaficarella@gmail.com
You can put this solution on YOUR website! here you have to use the law of sines
let tree make an angle of 83 deg.with the ground. (YZ)angle ZYX = 83deg
he walks 100 feet away from tree to point X (YX)angle YXZ= 33 deg
so remaining angle YZX = 64 deg
triangle YXZ is formed
sin A /a = sin B /b = sin C /c
Sin YZX/100 = sin YXZ/ YZ
sin 64/100 = sin 33/YZ
100 * sin 33/sin 64 = YZ
100*0.54/0.898= YZ
YZ= 60.13 feet the height of the tree
You can solve the problem in a similar way if the tilt is to the other side.
