SOLUTION: the diagonals of a square pqsr intersect at e. if pe=2x+6 and rq=6x-10, find the value of x
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Question 736287
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the diagonals of a square pqsr intersect at e. if pe=2x+6 and rq=6x-10, find the value of x
Answer by
solver91311(24713)
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Since it is a square, the two diagonals bisect each other and therefore PE is one half of RQ.
Solve for
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it