SOLUTION: the diagonals of a square pqsr intersect at e. if pe=2x+6 and rq=6x-10, find the value of x

Algebra ->  Angles -> SOLUTION: the diagonals of a square pqsr intersect at e. if pe=2x+6 and rq=6x-10, find the value of x       Log On


   



Question 736287: the diagonals of a square pqsr intersect at e. if pe=2x+6 and rq=6x-10, find the value of x

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Since it is a square, the two diagonals bisect each other and therefore PE is one half of RQ.



Solve for

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism