Question 736022: Solve for x: log16 base x÷log8 base x =3
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Solve for x: log16 base x÷log8 base x =3
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logx(16) / logx(8) = 3
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logx(16) = 3*logx(8)
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logx(16) - logx(8^3) = 0
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logx[16/8^3] = 0
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That implies 16/8^3 = x^0 = 1
That is a contradiction.
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Cheers,
Stan H.
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