SOLUTION: The number of particles N(t) emitted by a radio active substance varies with time, t, according to the law: N(t)=9.63x10^17e^-0.6t, Calculate the number of particles emitted when t

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: The number of particles N(t) emitted by a radio active substance varies with time, t, according to the law: N(t)=9.63x10^17e^-0.6t, Calculate the number of particles emitted when t      Log On


   

Question 735966: The number of particles N(t) emitted by a radio active substance varies with time, t, according to the law: N(t)=9.63x10^17e^-0.6t, Calculate the number of particles emitted when t=2??
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Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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The number of particles N(t) emitted by a radio active substance varies with time, t, according to the law:
N(t)=9.63x10^17e^-0.6t, Calculate the number of particles emitted when t=2??
:
N(t)=9.63%2A10%5E17%2Ae%5E%28-0.6t%29
replace t with 2
N(2)=9.63%2A10%5E17%2Ae%5E%28-0.6%2A2%29
N(2)=9.63%2A10%5E17%2Ae%5E%28-1.2%29
Find e^-1.2 on a calc
N(2)=9.63%2A10%5E17%2A.30119
N(2)= 2.9(10^17) particles when t=2