SOLUTION: Log5x-Log(2x-1)=Log7
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Question 735809
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Log5x-Log(2x-1)=Log7
Answer by
lwsshak3(11628)
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Log5x-Log(2x-1)=Log7
log[5x/(2x-1)]=log(7)
5x/(2x-1)=7
5x=14x-7
9x=7
x=7/9