SOLUTION:
A pharmacist has a 30% and 80% iodine solutions on hand. How many liters of each iodine dilution will be required to produce 8 liters of a 50% iodine mixture?
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A pharmacist has a 30% and 80% iodine solutions on hand. How many liters of each iodine dilution will be required to produce 8 liters of a 50% iodine mixture?
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Question 735595:
A pharmacist has a 30% and 80% iodine solutions on hand. How many liters of each iodine dilution will be required to produce 8 liters of a 50% iodine mixture? Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! .80X+.30(8-X)=.50*8
.80X+.24-.30X=4
.50X=40-.24
.50X=.16
X=.16/.5
X=3.2 LITERS ANS. FOR THE 80% SOLUTION IS USED.
PROOF:
.80*3.2+.30(8-3.2)=.50*8
2.56+.30*4.8=4
2.56+1.44=4
4=4
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