SOLUTION: find all solutions to the equations [0,2pie) 2sin^2x+3sinx+1=0

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Question 735477: find all solutions to the equations [0,2pie)
2sin^2x+3sinx+1=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find all solutions to the equations [0,2pie)
2sin^2x+3sinx+1=0
(2sinx+1)(sinx+1)=0
..
2sinx+1=0
sinx=-1/2
x=7π/6, 11π/6 (in Q3 and Q4 where sin<0)
..
sinx+1=0
sinx=-1
x=3π/2
solutions: x=7π/6, 11π/6, 3π/2