SOLUTION: If f(x)= cos(2x)-3sin(4x), find the exact value of f'(PIE/6)
The first step I thought of was cos(2A)= 1-Sin^2A because you'll need to make the cos into sin for the equation to
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-> SOLUTION: If f(x)= cos(2x)-3sin(4x), find the exact value of f'(PIE/6)
The first step I thought of was cos(2A)= 1-Sin^2A because you'll need to make the cos into sin for the equation to
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Question 735099: If f(x)= cos(2x)-3sin(4x), find the exact value of f'(PIE/6)
The first step I thought of was cos(2A)= 1-Sin^2A because you'll need to make the cos into sin for the equation to work. Thanks. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! If f(x)= cos(2x)-3sin(4x), find the exact value of f'(PIE/6)
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For[0,2π]
f(x)= cos(2x)-3sin(4x)
f(π/6)=cos(2π/6)-3sin(4π/6)
..
cos(2π/6)=cos(π/3)=1/2
sin(4π/6)=sin(2π/3)=√3/2 (in Q2 where sin>0)
..
f(π/6)=cos(2π/6)-3sin(4π/6)
=cos(π/3)-3sin(2π/3)
=1/2-3√3/2
=(1-3√3)/2
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