SOLUTION: log4(x+5)=3+log4(x+2) solve the logarithmic eqaution. be sure to reject any value that is not in the domain of the orginal logarithmic expressions

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: log4(x+5)=3+log4(x+2) solve the logarithmic eqaution. be sure to reject any value that is not in the domain of the orginal logarithmic expressions      Log On


   

Question 735016: log4(x+5)=3+log4(x+2)
solve the logarithmic eqaution. be sure to reject any value that is not in the domain of the orginal logarithmic expressions
Answer by fcabanski(1391) About Me  (Show Source):
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log4(x+5)=3+log4(x+2)


log4(x+5) - log4(x+2) =


Remember that log(x) - log(y) = log(x/y) and logx(y)=a means x^a = y


log4((x+5)/(x+2)) = 3


4^3 = x+5/x+2


64 = x+5/x+2


64x + 128 = x+5


63x = -123


x = -123/63 = approximately 1.9524

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