SOLUTION: how do you solve this on ti-84 calculator? Suppose a set of data is exactly Normally distributed with a mean of 6.8, mu=6.8, and a standard deviation of 1.1, sigma=1.1. Acc

Algebra ->  Probability-and-statistics -> SOLUTION: how do you solve this on ti-84 calculator? Suppose a set of data is exactly Normally distributed with a mean of 6.8, mu=6.8, and a standard deviation of 1.1, sigma=1.1. Acc      Log On


   



Question 734795: how do you solve this on ti-84 calculator?
Suppose a set of data is exactly Normally distributed with a mean of 6.8, mu=6.8, and a standard deviation of 1.1, sigma=1.1.

According to the 68-95-99.7 rule, we expect 68% of the observations in the data set to fall
between and .

Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose a set of data is exactly Normally distributed with a mean of 6.8, mu = 6.8, and a standard deviation of 1.1, sigma=1.1.
You don't use a calculator at all. Calculators won't take the place
of learning what's going on.

Instead of thinking the calculator will keep you from having to
learn the material, you must instead learn what the 68-95-99.7 rule 
is all about.

According to the 68-95-99.7 rule, 

1.  we expect 68% of the observations in the data set to fall
    between 1 standard deviation below the mean and 1 standard 
    deviation above the mean.

2.  we expect 95% of the observations in the data set to fall
    between 2 standard deviations below the mean and 2 standard 
    deviations above the mean.    

3.  we expect 99.7% of the observations in the data set to fall
    between 3 standard deviation below the mean and 3 standard 
    deviation above the mean.

You are asked to fill in these blanks:

We expect 68% of the observations in the data set to fall
between       and      .

So by the rule, we subtract 1 standard deviation 1.1 from the mean 6.8

and get 6.8 - 1.1 = 5.7  to go in the first blank, and

we add 1 standard deviation 1.1 to the mean 6.8 

and get 6.8 + 1.1 = 7.9  to go in the second blank.

we expect 68% of the observations in the data set to fall
between  5.7  and  7.9 .

Edwin