SOLUTION: I need help finding the price of a senior's ticket and a children's ticket. I know how to set up the problem (3s+1c=38 and 3s+2c=52), however I'm a bit stuck after that.
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-> SOLUTION: I need help finding the price of a senior's ticket and a children's ticket. I know how to set up the problem (3s+1c=38 and 3s+2c=52), however I'm a bit stuck after that.
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Question 734686: I need help finding the price of a senior's ticket and a children's ticket. I know how to set up the problem (3s+1c=38 and 3s+2c=52), however I'm a bit stuck after that. Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! (3s+1c=38 and 3s+2c=52)
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stack up your two equations:
3s+1c=38
3s+2c=52
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we solve by applying the "addition method".
Multiply both sides of the top equation by -1 and then combine with second:
-3s-1c = -38
3s+2c = 52
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c = 14 (number of child tickets)
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to find s, substitute above into:
3s+1c=38
3s+14=38
3s=24
s = 8 (number of student tickets)
