SOLUTION:
A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution with a 20% solution. How many gallons of each solution are needed?
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A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution with a 20% solution. How many gallons of each solution are needed?
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Question 734532:
A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution with a 20% solution. How many gallons of each solution are needed? Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! 100*.18=.20x+.12(100-x)
18=.20x+12-.12x
.20x-.12x=18-12
.08x=6
x=6/.08
x=75 gallons of 20% acid is used.
100-75=25 gallons of 12% acid is used.
proof:
100*18=.20*75+.12*25
18=15+3
18=18
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