SOLUTION: Subtract 2) 3x/x^2+3x-10 - 2x/x^2+x-6

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Question 734411: Subtract
2) 3x/x^2+3x-10 - 2x/x^2+x-6
Found 2 solutions by lynnlo, rothauserc:
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
subtraction:x(x-1)(x+5)(x-2)(x+3)

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
Fist step is to make all fractions have the same denominator,
(3x+(3x-10)*x^2) / X^2 - (2x+(x-6)*x^2) / x^2)
we can now combine numerators over the denominator x^2
(3x+(3x-10)*x^2 - 2x + (x-6)*X^2) / x^2
multiply the x^2 term in the numerator
(3x+3x^3-10x^2-2x-2x^3+6x^2) / x^2
combine like terms in numerator
(x^3-4x^2+x) / x^2
reduce by x
(x^2-4x+1) / x is the solution