You can put this solution on YOUR website! 2x+12/3x-15/2x^2-6x-20/x^2-10x+25
Factor:
[2(x+6)/3(x-5)]/[2(x-5)(x+2)/(x-5)^2]
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Invert the denominator and multiply:
[2(x+6)/3(x-5)]*{(x-5)^2/[2(x-5)(x+2)]}
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[2(x+6)/3] * {(x-5)^2/[2(x-5)^2*(x+2)]}
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Cancel 2,(x-5)^2 to get:
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[(x+6)/3]*{1/[(x+2)}
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= (x+6)/[3(x+2)]
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Cheers,
Stan H.
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