You can put this solution on YOUR website! Find two roots of (x-3)^2=25 without changing (x-3)^2 to a trinomial.
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(x-3)^2 - 5^2 = 0
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The form is the "difference of squares".
Factor:
(x-3-5)(x-3+5) = 0
(x-8)(x+2) = 0
x = 8 or x = -2
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Cheers,
Stan H.
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