SOLUTION: A season of football scores falls in a normal distribution with a mean of 35 and standard deviation of 6. What is the probability that a score was between 29 and 41?

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Question 734293: A season of football scores falls in a normal distribution with a mean of 35 and standard deviation of 6. What is the probability that a score was between 29 and 41?
Answer by stanbon(75887) About Me  (Show Source):
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A season of football scores falls in a normal distribution with a mean of 35 and standard deviation of 6. What is the probability that a score was between 29 and 41?
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z(41) = (41-35)/6 = 1
z(29) = (29-35)/6 = -1
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P(29 < x < 41) = P(-1< z < 1) = normalcdf(-1,1) = 0.6827
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Cheers,
Stan H.
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