SOLUTION: at 2:10 Joyce was 42 miles from home. At 2:30 she was 21 miles from home. find her average rate of travel. then find the slope. I do no that rate mean to divide problem but I am a

Algebra ->  Graphs -> SOLUTION: at 2:10 Joyce was 42 miles from home. At 2:30 she was 21 miles from home. find her average rate of travel. then find the slope. I do no that rate mean to divide problem but I am a      Log On


   



Question 734169: at 2:10 Joyce was 42 miles from home. At 2:30 she was 21 miles from home. find her average rate of travel. then find the slope. I do no that rate mean to divide problem but I am a little because I graph it can some one please help me to understand a little better

thanks Desiree

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
at 2:10 Joyce was 42 miles from home. At 2:30 she was 21 miles from home.
find her average rate of travel. then find the slope.
:
The travel time from 2:10 to 2:30 is 20 min which is: 20/60 = 1%2F3 hr
During this time he traveled 21 mi
:
Speed = dist/time
:
s = 21%2F%281%2F3%29
s = 21 * 3
s = 63 mph
:
The equation, where d = distance from home
d = -63t + 42
:
The slope is -63
:
the graph, vert is distance from home, horizontal is time in hrs
+graph%28+300%2C+200%2C+-.5%2C+1%2C+-10%2C+50%2C+-63x%2B42%29+