SOLUTION: find three consecutive integers such that two times the second is three more than the first.

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Question 734123: find three consecutive integers such that two times the second is three more than the first.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

2x = 3 + (x-1)
2x = x + 2
x = 2

The integers are 1, 2, and 3.