SOLUTION: Please help me write this expression as a single logarithm:
-2log(1/x)+(1/3)log(sqrt(x))
the base of each log is 3
I know that first you have to switch the coefficients an
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-> SOLUTION: Please help me write this expression as a single logarithm:
-2log(1/x)+(1/3)log(sqrt(x))
the base of each log is 3
I know that first you have to switch the coefficients an
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Question 734032: Please help me write this expression as a single logarithm:
-2log(1/x)+(1/3)log(sqrt(x))
the base of each log is 3
I know that first you have to switch the coefficients and make them exponents, and when your exponent is 1/3 it is really the cube root, in this case, of sqrt(x). But how do you go from there? How can you cube root a square root? And when you put the 2 to be an exponent does the negative sign go with it or does it stay part of the log? Please help me, I am so confused. Answer by josgarithmetic(39613) (Show Source):
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