SOLUTION: Help please! H=vt +1/2at^2 H=25,000 t=10 v=2,000 Does the acceleration exceed 3g(1g=32ft/sec^2)? Thank you so much.

Algebra ->  Systems-of-equations -> SOLUTION: Help please! H=vt +1/2at^2 H=25,000 t=10 v=2,000 Does the acceleration exceed 3g(1g=32ft/sec^2)? Thank you so much.       Log On


   

Question 733739: Help please!
H=vt +1/2at^2
H=25,000
t=10
v=2,000
Does the acceleration exceed 3g(1g=32ft/sec^2)?
Thank you so much.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
H=vt +1/2at^2
H=25,000
t=10
v=2,000
Does the acceleration exceed 3g(1g=32ft/sec^2)?
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H=vt + at^2/2
25000 = 2000*10 + 50a
50a = 5000
a = 100 ft/sec/sec, > 96