SOLUTION: two girls' ages, 11 years apart, when multiplied, make 210. The sum of their ages is?

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Question 733591: two girls' ages, 11 years apart, when multiplied, make 210. The sum of their ages is?
Found 2 solutions by josmiceli, MathLover1:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let their ages be +x+ and +x+%2B+11+
given:
+x%2A%28+x+%2B+11+%29+=+210+
+x%5E2+%2B+11x+-+210+=+0+
I notice that +210+=+21%2A10+ and +21+-+10+=+11+
+%28+x+%2B+21+%29%2A%28+x+-+10+%29+
+x+=+10+ ( ignore x = -21 )
+x+%2B+11+=+21+
The sum of their ages is +21+%2B+10+=+31+


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
let one girl's be x and another y
if two girls' ages, 11 years apart, then x-y=11...eq.1
when multiplied,x%2Ay=210 .......eq.2
The sum of their ages is x%2By
start with:
x-y=11...eq.1
x%2Ay=210 .......eq.2
____________________________
x-y=11...eq.1...solve for y
x-11=y...eq.1...substitute y in eq.2
x%2A%28x-11%29=210 .......eq.2.....solve for y
x%5E2-11x=210
x%5E2-11x-210=0......use quadratic formula


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%28-%28-11%29+%2B-+sqrt%28%28-11%29%5E2-4%2A1%2A%28-210%29+%29%29%2F%282%2A1%29+

x+=+%2811+%2B-+sqrt%28121%2B840%29+%29%29%2F2+

x+=+%2811+%2B-+sqrt%28961%29+%29%29%2F2+

x+=+%2811+%2B-+31+%29%29%2F2+

solutions:
x+=+%2811+%2B+31+%29%2F2+
x+=+42%2F2+
highlight%28x+=+21+%29
and
x+=+%2811+-31+%29%2F2+
x+=+-20%2F2+
x+=+-10+.....since we are looking for age, we do not need this solution
now find y
x-11=y
21-11=y
highlight%2810=y%29

so, one girl's be highlight%28x+=+21+%29 and another highlight%2810=y%29 and the sum of their ages is x%2By=21%2B10=highlight%2831%29