SOLUTION: use the rational zero theorem and descartes’ rule of signs to assist you in finding all real and imaginary roots for x^4+2^3-3x^2-4x+4=0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: use the rational zero theorem and descartes’ rule of signs to assist you in finding all real and imaginary roots for x^4+2^3-3x^2-4x+4=0      Log On


   



Question 733248: use the rational zero theorem and descartes’ rule of signs to assist you in finding all real and imaginary roots for x^4+2^3-3x^2-4x+4=0
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
(Assuming you mean the second term is 2x^3)
x%5E4%2B2x%5E3-3x%5E2-4x%2B4=0, ___________ 2 sign changes. Expect 2 positive roots.

Let x become -x.
x%5E4%2B2%28-x%29%5E3-3x%5E2-4%28-x%29%2B4=x%5E4-2x%5E3-3x%5E2%2B4x%2B4,_________ 2 sign changes. Expect 2 negative roots.

Choices for checking roots would be -1, -2, -4, +1, +2, +4.

Use of synthetic division shows -2 root, +2 NOT root, -1 NOT root, +1 root.
So far, Real roots seem to be -2 and +1.

The polynomial now rendered to check is x%5E2%2Bx-2. Use of general solution to quadratic equation (even though this one is factorable) indicates roots -2 and +1. They occur in the factorization for the originally given degree 4 polynomial TWICE.

Roots are all REAL numbers, and are -2, +1, -2 (again), and +1 (again).
highlight%28x%5E4%2B2%5E3-3x%5E2-4x%2B4=%28x%2B2%29%5E2%2A%28x-1%29%5E2%29.