SOLUTION: Kendra has $4.25 in dimes and quarters. If she has 3 times as many quarters as dimes, how many of each coin does she have?

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Question 733094: Kendra has $4.25 in dimes and quarters. If she has 3 times as many quarters as dimes, how many of each coin does she have?
Found 3 solutions by stanbon, lynnlo, ikleyn:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Kendra has $4.25 in dimes and quarters. If she has 3 times as many quarters as dimes, how many of each coin does she have?
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Quantity Equation: q = 3d
Value Equation: 10d + 25q = 425 cents
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Substitute for "q" and solve for "d":
10d + 25(3d) = 425
85d = 425
d = 5 (# of dimes)
----
Solve for "q":
q = 3d
q = 15 (# of quarters)
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Cheers,
Stan H.
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Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
DIMES=20=$2.00
QUARTERS=======9======$2.25
TOTAL====$4.25

Answer by ikleyn(53201) About Me  (Show Source):
You can put this solution on YOUR website!
.
Kendra has $4.25 in dimes and quarters. If she has 3 times as many quarters as dimes,
how many of each coin does she have?
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This problem is ideal to solve it mentally, without using equations.


Indeed, according to the problem, we can group the coins in sets, 
each containing 3 quarters and one dime.


Each such set is worth 3*25 + 10 = 85 cents.

Hence, the number of sets is  425%2F85 = 5.


So, Kendra has 5 dimes and 15 quarters.


CHECK.  5*10 + 15*25 = 425 cents = $4.25.   ! correct !

Solved.

The solution and the answer in the post by @lynnlo both are incorrect.