SOLUTION: Write the standard equation for the parabola with the given set of characteristics. Then graph the parabola axis of symmetry: y=0 focus: (4,0) vertex: (0,0)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write the standard equation for the parabola with the given set of characteristics. Then graph the parabola axis of symmetry: y=0 focus: (4,0) vertex: (0,0)      Log On


   



Question 732374: Write the standard equation for the parabola with the given set of characteristics. Then graph the parabola
axis of symmetry: y=0
focus: (4,0)
vertex: (0,0)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write the standard equation for the parabola with the given set of characteristics. Then graph the parabola
axis of symmetry: y=0
focus: (4,0)
vertex: (0,0)
***
This is a parabola that opens rightward:
Its basic equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of vertex
For given parabola:
p=4 (distance from vertex to focus on the axis of symmetry)
4p=16
Equation: y^2=16x
see graph below as a visual check:
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+4x%5E.5%2C-4x%5E.5%29+