SOLUTION: A cyclist rode the first 22-mile portion of his work at a constant speed. For the 14- mile cool down portion of his workout, he reduced his speed by 4 miles per hour. Each portion

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A cyclist rode the first 22-mile portion of his work at a constant speed. For the 14- mile cool down portion of his workout, he reduced his speed by 4 miles per hour. Each portion       Log On


   



Question 732120: A cyclist rode the first 22-mile portion of his work at a constant speed. For the 14- mile cool down portion of his workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the cyclist's speed during the first portion and find his speed during the cool down portion
Answer by lwsshak3(11628) About Me  (Show Source):
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A cyclist rode the first 22-mile portion of his work at a constant speed. For the 14- mile cool down portion of his workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the cyclist's speed during the first portion and find his speed during the cool down portion.
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let x=speed during first portion(22 mi)
x-4=speed during cool down portion(14 mi)
travel time=distance/speed
..
22/x=14/(x-4)
14x=22x-88
8x=88
x=11
x-4=7
speed during first portion(22 mi)=11 mph
speed during cool down portion(14 mi)=7 mph