SOLUTION: I am having a lot of trouble with this problem. Any help would be appreciated Solve for x: 7 + sqrt(2x-5) = 12 7 + sqrt(2x-5) = 12 -subtract 7 from both sides (sqrt(2x-5)^2=5^2

Algebra ->  Square-cubic-other-roots -> SOLUTION: I am having a lot of trouble with this problem. Any help would be appreciated Solve for x: 7 + sqrt(2x-5) = 12 7 + sqrt(2x-5) = 12 -subtract 7 from both sides (sqrt(2x-5)^2=5^2       Log On


   

Question 73204: I am having a lot of trouble with this problem. Any help would be appreciated
Solve for x: 7 + sqrt(2x-5) = 12
7 + sqrt(2x-5) = 12 -subtract 7 from both sides
(sqrt(2x-5)^2=5^2
2x-5+5=25 +5
2x/2=20/2 -> 10
check: 7 + sqrt(2(10)-5 =12 ->7 + sqrt(15)=12 ***this is where i get stuck, i dont think the answer is right
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x: 7 + sqrt(2x-5) = 12
:
7 + sqrt(2x-5) = 12 -subtract 7 from both sides
:
(sqrt(2x-5)^2=5^2
:
2x - 5 + 5 = 25 + 5
Right here you should have
2x = 30
x = 30/2
x = 15
:
Check:
7 + Sqrt(2(15) - 5) = 12
7 + Sqrt(25) = 12
:
Your method was right, just a small math error. But you checked your solution in
the original equation and found out. That's good