SOLUTION: Help to factor expression completely 6x^3 + 48

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Question 731932: Help to factor expression completely
6x^3 + 48
Answer by fcabanski(1391) About Me  (Show Source):
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Factor out a 6: 6(x^3 + 8)


Inside the parentheses is now the sum of two cubes (8=2^3).


(a^3 + b^3) = (a+b)(a^2 -ab + b^2).


a=x and b=2


6((x+2)(x^2 -2x +4))

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