SOLUTION: [(tanx-cotx)/(tanx+cotx)]+ 2cos^2x = 1
I have tried 2 different ways so far and I still cant seem to get the right answer
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-> SOLUTION: [(tanx-cotx)/(tanx+cotx)]+ 2cos^2x = 1
I have tried 2 different ways so far and I still cant seem to get the right answer
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Question 731848: [(tanx-cotx)/(tanx+cotx)]+ 2cos^2x = 1
I have tried 2 different ways so far and I still cant seem to get the right answer Answer by nshah11(47) (Show Source):
You can put this solution on YOUR website! (tan(x) - cot(x))/(tan(x) + cot(x)) + 2cos^2(x) = 1
Simplifying the LHS:
(sin(x)/cos(x) - cos(x)/sin(x))/(sin(x)/cos(x) + cos(x)/sin(x)) + 2cos^2(x)
= (sin^2(x) - cos^2(x))/1 + 2cos^2(x) = sin^2(x) + cos^2(x) = 1
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