SOLUTION: find the equation of the line in slope intercept form that is perpendicular to y=-1/4x+3 and passes through (3/2, 5)
I understand that I must put this in point slope form... But
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-> SOLUTION: find the equation of the line in slope intercept form that is perpendicular to y=-1/4x+3 and passes through (3/2, 5)
I understand that I must put this in point slope form... But
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Question 731701: find the equation of the line in slope intercept form that is perpendicular to y=-1/4x+3 and passes through (3/2, 5)
I understand that I must put this in point slope form... But I'm not very proficient when it comes to fractions... Answer by mananth(16946) (Show Source):
y = - 1/ 4 x + 3
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = - 1/4
The slope of a line perpendicular to the above line will be the negative reciprocal 4
Because m1*m2 =-1
The slope of the required line will be 4
m= 4 ,point ( 1.5 , 5 )
Find b by plugging the values of m & the point in
y=mx+b
5 = 6 + b
b= -1
m= 4
The required equation is y = 4 x -1
m.ananth@hotmail.ca
