SOLUTION: A heater raises the temperature 15 degrees in 24 minutes. With a second heater also in operation, the change takes place in 6 minutes. How long would it take the second heater wo

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A heater raises the temperature 15 degrees in 24 minutes. With a second heater also in operation, the change takes place in 6 minutes. How long would it take the second heater wo      Log On


   



Question 731542: A heater raises the temperature 15 degrees in 24 minutes.
With a second heater also in operation, the change takes place in 6 minutes.
How long would it take the second heater working alone to produce the same temperature change?

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Are rates such as those really uniform? That's suspicious.

Anyway, let the rates in degrees per minute b e+m+=+15%2F24, and m%2Bn+=15%2F6, so we do not know rate n. We are expected to assume that when both heaters operate together, the rates are simply summed. We would do this:

m + n = BOTH-TOGETHER
15%2F24%2Bn=15%2F6
n=15%2F6-15%2F24
n=%2815%2F6%29%284%2F4%29-15%2F24
You can finish from here.