Question 731409: Csc(3x-15)=sec(10+2x)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Csc(3x-15)=sec(10+2x)
1/sin(3x-15)=1/cos(2x+10)
[cos(2x+10)/sin(3x-15)]=1
For this equation to be true, the angles for both sin and cos must be=π/4
..
2x+10=π/4
2x=π/4-10
x=(π/4-10)/2
x≈-4.6073
..
3x-15=π/4
x=π/4+15)/3
x≈5.2618
Check:with calculator
cos(2x+10)=cos(2*-4.6073+10)≈0.7071
sin(3x-15)=sin(3*5.2618-15)=0.7071
[cos(2x+10)/sin(3x-15)]=0.7071/0.7071=1
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