SOLUTION: find the equation of the line though (-2, -6) perpendicular to the line y= (1/3)x + 4/3

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Question 731405: find the equation of the line though (-2, -6) perpendicular to the line y= (1/3)x + 4/3
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The line perpendicular to y=+%281%2F3%29x+%2B+4%2F3 will have a slope of -3/1, because perpendicular lines in a plane have slopes which are negative reciprocals of each other.

Knowing the slope, -3, and the point which must be in this new line, (-2, -6), we can use the point-slope form for a line to write the equation and then simplify:

Point-Slope form for a line
highlight%28y-y%5B0%5D=m%28x-x%5B0%5D%29%29
y=m%28x-x%5B0%5D%29%2By%5B0%5D
Substituting coordinate values of the given point to be contained and also the slope,
y=-3%28x-%28-2%29%29%2B%28-6%29
y=-3%28x%2B2%29-6
y=-3x-6-6
The line is:______highlight%28y=-3x%29