SOLUTION: $1000 was invested altogether. The first investment yielded a 15% profit, but the second investment yielded a 10% loss. Altogether this was equivalent to a 6% loss. How much in

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Question 73136: $1000 was invested altogether. The first investment yielded a 15% profit, but the second investment yielded a 10% loss. Altogether this was equivalent to a 6% loss. How much in each investment?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
$1000 was invested altogether. The first investment yielded a 15% profit, but the second investment yielded a 10% loss. Altogether this was equivalent to a 6% loss. How much in each investment?
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Let amt of 15% investment be "x" ; Interest will be 0.15x
Amt of 10% investment is "1000-x": Interest will be 0.10(1000-x)=100-0.1x
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EQUATION:
Int - Int = -0.06(1000)
0.15x - (100-0.10x) = -0.06(1000)
0.15x-100+0.10x = -60
0.05x=40
x=$800 (amt invested at 15%)
1000-x = $200 (amt invested at 10%)
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Cheers,
Stan H.