SOLUTION: 3. A ball is dropped vertically from a height of 80 meters. After each bounce, the ball reaches a maximum height equal to 60 percent of maximum height of the previous bounce. a. W

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Question 731077: 3. A ball is dropped vertically from a height of 80 meters. After each bounce, the ball reaches a maximum height equal to 60 percent of maximum height of the previous bounce.
a. Write the first three terms of the sequence. Explain how you know what they are.
b. Find the height to the nearest tenth of a meter of the ball after the eighth bounce. Show and
explain your work.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
After 1st bounce,
+h+=+.6%2A80+
After 2nd bounce,
+h+=+.6%2A%28+.6%2A80+%29+
After 3rd bounce,
+h+=+.6%2A%28+.6%2A%28+.6%2A80+%29+%29+
So, the general formula is
After the +n+th bounce,
+h+=+.6%5En+%2A+80+
----------------
(a)
+.6%2A80+=+48+m
+.36%2A80+=+28.8+m
+.216%2A80+=+17.28+m
-------------------
(b)
+h+=+.6%5E8+%2A80+=+.0168%2A80+
+h+=+1.344+ m