SOLUTION: The sum of two number is 60 and their difference is 43. What is The difference of their squares?

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Question 731026: The sum of two number is 60 and their difference is 43. What is The difference of their squares?
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
Call the bigger number x and the smaller number y.


x+y = 60 and x-y = 43


From equation 1: x = 60-y. Substitute that into equation 2: 60-y-y = 43


60-2y = 43


17 = 2y


17/2 = y


x = 60-y = 60 - 17/2 = 120/2 - 17/2 = 103/2


x%5E2+=+%28103%2F2%29%5E2+=+10609%2F4


y%5E2+=+%2817%2F2%29%5E2+=+289%2F4


The difference of the squares is x%5E2+-+y%5E2+=+10609%2F4+-+289%2F4+=+10320%2F4+=+2580

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