SOLUTION: Im confuse to how to do this but can you help to solve this equation... write the equation of the line and graph. 1) slope=-2/3, y-intercept=-8 2) slope=3, cointains point(2,1)

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Question 7310: Im confuse to how to do this but can you help to solve this equation...
write the equation of the line and graph.
1) slope=-2/3, y-intercept=-8
2) slope=3, cointains point(2,1)
3) passes through(-2,2) and (2,-10)
thank you very much! it will really help me alot if you help with this one..
Answer by ichudov(507) About Me  (Show Source):
You can put this solution on YOUR website!
1) this one is easy. slope -2/3 means that there us a -2%2F3%2Ax+ part of the equation. Y=intercept of -8 means that the constant is -8.
y=-%282%2F3%29%2Ax-8
2) try doing it yourself, write y=3x+a. For point 2, 1 (x=2, y=1), write: 1=3*2+a, solve for a.
3)
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, 2) and (x2, y2) = (2, -10).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-10-2%29%2F%282--2%29+=+-3.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -3%2A-2+%2Bb+=+-4. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=2--3%2A-2+=+-4.

y=(-3)x + (-4)

Your graph: