Remember that log(base n) (x) + log(base n) (y) = log(base n) (xy)
LogBase4(x-2)+LogBase4(x+10)=3
logbase((x-2)*(x+10)) = 3
logbase4(x^2 + 8x -20) = 3
Recall that logbasen (x) = y if and only if n^y = x.
(x+14)(x-6) = 0
x=-14 and x=6
The log of a negative number is imaginary. So only x=6 works. -14 results in logbase4 (-16) + logbase4 (-4) = 3 . The log of negative numbers isn't real.
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