Question 730940: The sum of the square of two consecutive odd integers is 2 more than 6 times their sum. Find the numbers.... Please! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The sum of the square of two consecutive odd integers is 2 more than 6 times their sum. Find the numbers....
----------
1st: 2x-1
2nd: 2x+1
--------------------
Equation:
(2x-1)^2 + (2x+1)^2 = 6[2x-1+2x+1]+2
----
4x^2 -4x + 1 + 4x^2 + 4x + 1 = 24x+2
---
8x^2 = 24x
8x^2-24x = 0
8x(x-3) = 0
x = 0 or x = 3
============================================
Cheers,
Stan H.
(