SOLUTION: How do I write in slope-intercept form for the line that satisfies the condition with a slope of {{{ 7/18 }}} and passes through (4,-20) I've tried the point slope formula {{{ y

Algebra ->  Linear-equations -> SOLUTION: How do I write in slope-intercept form for the line that satisfies the condition with a slope of {{{ 7/18 }}} and passes through (4,-20) I've tried the point slope formula {{{ y      Log On


   



Question 730936: How do I write in slope-intercept form for the line that satisfies the condition with a slope of +7%2F18+ and passes through (4,-20)
I've tried the point slope formula +y-y1=m%28x-x1%29 but I'm having trouble understanding how to plug-in and distribute the numbers.

Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do I write in slope-intercept form for the line that satisfies the condition with a slope of +7%2F18+ and passes through (4,-20)
I've tried the point slope formula +y-y1=m%28x-x1%29 but I'm having trouble understanding how to plug-in and distribute the numbers.
-----
y--20 = (7/18)(x-4)
----
y+20 = (7/18)x - (28/18)
-------
y = (7/18)x - (14/9)-20
---
y = (7/18)x - 21 5/9
----------------------------------
Cheers,
Stan H.
===========

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do I write in slope-intercept form for the line that satisfies the condition with a slope of 7/18 and passes through (4,-20).
***
You can use the point-slope or slope-intercept formula.
slope-intercept method: y=mx+b, m=slope, b=y-intercept
y=7x/18+b
solve for b using coordinates of given point (4,-20) on the line.
-20=7*4/18+b
-20=28/18+b
b=-20-14/9=-180/9-14/9=-194/9
Equation:y=7x/18-194/9
...
point-slope method: y-y1=m(x-x1)
y+20=7/18(x-4)
18y+360=7(x-4)=7x-28
18y=7x-388
y=7x/18-388/18
y=7x/18-194/9