SOLUTION: how do I solve the following equation in general form? 4x-y^2=2y+13

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Question 730765: how do I solve the following equation in general form?
4x-y^2=2y+13
Found 2 solutions by lynnlo, josgarithmetic:
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
X=y2/4+y/2+13/4

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
How? Just solve the equation for x in terms of y.
Your question is now edited. Equation was written in the belief you wanted y squared and the exponential symbol was present but no exponent shown.

4x=y%5E2%2B2y%2B13
x=%281%2F4%29y%5E2%2B%281%2F2%29y%2B13%2F4
Note that the axis of symmetry is horizontal and the parabola opens to the right.